KCNJ15 Polyclonal Antibody (E-AB-13569)
For research use only.
Verified Samples |
Verified Samples in IHC: Human liver cancer, Human cervical cancer |
Dilution | IHC 1:50-1:200 |
Isotype | IgG |
Host | Rabbit |
Reactivity | Human, Mouse, Rat |
Applications | IHC |
Clonality | Polyclonal |
Immunogen | Synthetic peptide of human KCNJ15 |
Abbre | KCNJ15 |
Synonyms | ATP sensitive inward rectifier potassium channel 15, ATP-sensitive inward rectifier potassium channel 15, Inward rectifier K(+) channel Kir1.3, Inward rectifier K(+) channel Kir4.2, Inward rectifier K+ channel KIR4.2, inwardly rectifying subfamily J member 15 |
Swissprot | |
Cellular Localization | Membrane. |
Concentration | 0.2 mg/mL |
Buffer | Phosphate buffered solution, pH 7.4, containing 0.05% stabilizer and 50% glycerol. |
Purification Method | Affinity purification |
Research Areas | Metabolism, Neuroscience, Signal Transduction |
Conjugation | Unconjugated |
Storage | Store at -20°C Valid for 12 months. Avoid freeze / thaw cycles. |
Shipping | The product is shipped with ice pack,upon receipt,store it immediately at the temperature recommended. |
background | Potassium channels are present in most mammalian cells, where they participate in a wide range of physiologic responses. The protein encoded by this gene is an integral membrane protein and inward-rectifier type potassium channel. The encoded protein has a greater tendency to allow potassium to flow into a cell rather than out of a cell. Eight transcript variants encoding the same protein have been found for this gene. |
Other Clones
{{antibodyDetailsPage.numTotal}} Results
-
{{item.title}}
Citations ({{item.publications_count}}) Manual MSDS
Cat.No.:{{item.cat}}
{{index}} {{goods_show_value}}
Other Formats
{{formatDetailsPage.numTotal}} Results
Unconjugated
-
{{item.title}}
Citations ({{item.publications_count}}) Manual MSDS
Cat.No.:{{item.cat}}
{{index}} {{goods_show_value}}
-
IF:{{item.impact}}
Journal:{{item.journal}} ({{item.year}})
DOI:{{item.doi}}Reactivity:{{item.species}}
Sample Type:{{item.organization}}
-
Q{{(FAQpage.currentPage - 1)*pageSize+index+1}}:{{item.name}}